What is the limit of #(4x)/(x-6)+(5x)/(x+6)# as x approaches infinity?
1 Answer
Mar 18, 2016
The limit is
Explanation:
# = lim_(xrarroo)(4)/((1-6/x)) = 4/(1-0) = 4#
And
# = lim_(xrarroo)(5)/((1+6/x)) = 5/(1+0) = 5#
Therefore,
# = 4+5=9#