Question

Is `2pi*sqrt(l/g)` reducable to a dimension of time?

Answer 1

Yes. Yes it is.

Explanation:

This equation is the period of a simple pendulum. Assuming your `l` stands for length, and `g` stands for gravity, we can rewrite this problem as

Period `= 2pi*sqrt(L/(L/T^2))`

Rewriting your fraction inside the `sqrt()` symbol,

Period `=2pi*sqrt(L*T^2/L)`

Cancelling terms and knowing that square roots cancel powers of 2, we get,

Period `=2pi*T`

So yes, this equation is reducible to a unit of time.