What is the derivative of #arctan(x-1)#?
1 Answer
Mar 18, 2016
Explanation:
We must first know the derivative of
#d/dxarctan(x)=1/(1+x^2)#
According to the chain rule, we see that
#d/dxarctan(f(x))=1/(1+(f(x))^2)*f'(x)#
So, for
#d/dxarctan(x-1)=1/(1+(x-1)^2)*1#
#=1/(1+(x^2-2x+1)#
#=1/(x^2-2x+2)#