How do you condense $log(6x)+log(4x)$ ?

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Answer 1 · 2016-03-20T00:50:49

Using the product rule of logarithms $log_a x + log_a y = log_a (xy)$
we have that

$log 6x+log 4x=log 24x^2$

How do you condense log(6x)+log(4x)log(6x)+log(4x)?