An electric toy car with a mass of #8 kg# is powered by a motor with a voltage of #2 V# and a current supply of #4 A#. How long will it take for the toy car to accelerate from rest to #8/3 m/s#?

1 Answer
Mar 21, 2016

#= 3.56 "s"#

Explanation:

The power input is the product of the voltage and the current.

#P = IV#

#= (2 "V") * (4 "A")#

#= 8 "W"#

The change in kinetic energy for the car is

#Delta "KE" = 1/2 m (v^2 - v_0^2)#

#= 1/2 (8 "kg") ((8/3 "m/s")^2 - (0 "m/s")^2)#

#= 28.4 "J"#

Thus, the time needed is the energy divided by the power.

#t = frac{Delta "KE"}{P}#

#= frac{28.4 "J"}{8 "W"}#

#= 3.56 "s"#