Question

How do you condense `log (5 x) + log (2 x)`?

Answer 1

`log(5x)+log(2x)` `=log (10x^2)`

Explanation:

`log(5x)+log(2x)`
`=log(5x*2x)`-> use property`log_bx+log_by=log_b(xy)`
`=log (10x^2)`