Question

How do you simplify `log_10(1000)+log_10(0.01)`?

Answer 1

`log_10(1000)+log_10(0.01)=1`

Explanation:

`log_10(1000)+log_10(0.01)`
`=log_10 10^3 +log_10 10^-2`
`=3 log_10 10 -2 log_10 10` -> use property `log_b x^n = n log _b x`
`=3(1)-2(1)`->use property`log_b b=1`
`=3-2`
`=1`