Question

How do you simplify `e^lnx`?

Answer 1

`e^lnx=x`

Explanation:

let `y=e^lnx`
`ln y=lne^lnx`->Take ln of both sides
`lny = lnx * ln e` -> use the property `log_b x^n = nlog_b x`
`lny=lnx(1)`-> `ln_e e = 1`-> from the property `log_b b = 1`
`lny = ln x`
Therefore `y=x`