How many atoms are in 183 g of calcium?

1 Answer
anor277
Mar 24, 2016

There are approx. 4.5xxN_A" calcium atoms" where N_A = "Avogadro's number", 6.02247xx10^23 mol^-1.

Explanation:

It is a fact that 40.078 g calcium contains "Avogadro's number" of calcium atoms. "Avogadro's number" is thus the link between the macro world of grams and kilograms, that which we can directly measure, and the micro world of atoms and molecules, about which we can conceive.

So moles of Ca = (183.08*g)/(40.078*g*mol^-1) =" approx. "4.5*mol.

"Number of calcium atoms "= 4.5*molxx6.02247xx10^23*mol^-1 = ?? "how many calcium atoms"

How did I know that 1 mol of calcium has a mass of 40.078 g?

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