If #13m=5n#, then what is #m/n#?

2 Answers
Mar 25, 2016

#m/n=5/13#

Explanation:

Divide both sides by #n#.

#(13m)/n=(5n)/n#

The #n# terms will cancel on the right hand side.

#(13m)/n=(5color(red)(cancel(color(black)(n))))/color(red)(cancel(color(black)(n)))#

#(13m)/n=5#

Divide both sides by #13#. Recall that this is the same as multiplying both sides by #1//13#.

#1/13((13m)/n)=5(1/13)#

Now, on the left side, we see that the #13#s will cancel, since they are present in the numerator and the denominator.

#1/color(red)(cancel(color(black)(13)))((color(red)(cancel(color(black)(13)))m)/n)=5/13#

#m/n=5/13#

Mar 25, 2016

#" "m/n=5/13#

Explanation:

Write as #13xxm=5xxn#

#color(blue)("Shortcut method")#

Using the principle that if you move something that multiplies to the other side of the = it becomes divide.

By sight: #color(green)(m/n=5/13)#

#color(brown)("Not that the shortcut method comes from first principles")#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Using first principles")#

Divide both sides by n giving

#" "13xxm/n=5xx n/n#

But #n/n=1# giving

#" "13xxm/n=5#

Divide both sides by 13 giving

#" "13/13xxm/n=5/13#

But #13/13 = 1# giving

#" "color(green)(m/n=5/13)#