Question

For what values of x, if any, does `f(x) = 1/((x+2)(x+9))` have vertical asymptotes?

Answer 1

vertical asymptotes at x = -2 , x = -9

Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation/s let the denominator equal zero.

solve : (x +2)(x +9 ) = 0 → x = - 2 , x = -9

Here is the graph of the function.
graph{1/((x+2)(x+9)) [-10, 10, -5, 5]}