Question

A charge of `18 C` passes through a circuit every `24 s`. If the circuit can generate `18 W` of power, what is the circuit's resistance?

Answer 1

`=32 Omega`

Explanation:

Current ,`I=Q/t=18/24=0.75A`
Again
Power `P= I^2*R`
Or,`R= P/I^2=18/(0.75)^2=32 Omega`