How do you solve #2n-4(n-3)=-(n-2)#?

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Answer 1 · 2016-03-28T01:55:40

#n=10#

#1#. Start by expanding on both sides of the equation.

#2n-4(n-3)=-(n-2)#

#2n-4n+12=-n+2#

#2#. Bring all terms with #n# to the left side and all constant terms to the right.

#2n-4n+n=2-12#

#3#. Simplify.

#-n=-10#

#4#. Divide both sides by #-1#.

#color(green)(|bar(ul(color(white)(a/a)n=10color(white)(a/a)|)))#