How do you determine if f(x)=2x53x2+2 is an even or odd function?

1 Answer
Mar 28, 2016

Neither

Explanation:

To determine if a function is even/odd the following applies.

• If f(x) = f( -x) then f(x) is even , x

Even functions have symmetry about the y-axis.

• If f( -x) = - f(x) then f(x) is odd , x

Odd functions have symmetry about the origin.
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Test for even :

f( -x) =2(x)53(x)2+2=2x53x2+2

since f(x) ≠ f( -x) , then f(x) is not even.
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Test for odd :

f(x)=(2x53x2+2)=2x5+3x22

since -f(x) ≠ f( -x) , then f(x) is not odd.