Question

What is the moment of inertia of a pendulum with a mass of `8 kg` that is `2 m` from the pivot?

Answer 1

`I= m*r^2 = 8*2^2= 2^5=32`

Explanation:

A pendulum you can treat as point mass of 8 kg, with this in mind you can simply use the straight forward formula `I = mr^2`
In general the mass moment of inertia `I_m = int r^2dm`
`I= m*r^2 = 8*2^2= 2^5=32`