How do you solve #x=11+2y# and #7x+2y=13# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Binayaka C. Mar 29, 2016 #x=3 ; y= -4# Explanation: Substituting #x=11+2y# on equation we get #7(11+2y)+2y=13 or 14y+2y=13-77 or 16y =-64 or y= -4 #; Putting y=-4 we get #x=11+2*(-4)=3#[Ans] Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 4998 views around the world You can reuse this answer Creative Commons License