Two charges of -7 C and -4 C are positioned on a line at points -9 and 7 , respectively. What is the net force on a charge of 4 C at -2 ?

1 Answer
Mar 29, 2016

5.14x 10^9 Newtons

Explanation:

The charges you have described are very large, so the Forces are also very large. Usually Coulombs are measured in micro (10^-6)
or nano (10^-9). Anyway, here is what I did, I hope it helps.

Since the charges are in line, we do not have to find the components of any of the vectors.

The questions is about Electric Fields. Every charge creates an electric field. The strength of the field is dependent on the magnitude of the charge. (In this case it is -4C and-7C). Here is a picture of an electric field:
enter image source here

Similarly, the charges from the above question will repel each other, since they are both negative.

Here is the math.

You can calculate the strength of an electric field from the equation: E=(kq)/r^2 . The "k" is a constant called Coulomb's Constant and it is 8.99 X10^9 Nm^2/C^2. More can be read about here

To calculate force of a charge, we use the equation F=qE.

From here it is a matter of identifying your charges and calculating. For me:
q_1= -4C
q_2= -7C

The electric field of q_2 is E_q= k q_2/r^2. If we substitute or variables, we get E_q= 8.99 X10^9 (-4)/7^2. This is Eq= 1.28x10^9 N/C

Now that we have found the Electric Field of q_2, we can find the Force on q_1 by using the F=qE equation. When we substitute we get F= (-4) 1.28x10^9.

Therefore the force of q_2 on q_1 at -2 is F= 5.14x10^9 N.

Here is a good animation and activity: here This animation allow you to see how the force increses as charges are placed nearer or farther away from each other.