How do you simplify #e^(2+lnx) #? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Konstantinos Michailidis Mar 31, 2016 It is #e^(2+lnx)=e^2*e^(lnx)=e^2*(x)=x*e^2# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 5491 views around the world You can reuse this answer Creative Commons License