Question

How do you find the limit of `abs(x-2) / (x-2)` as x approaches `2^+`?

Answer 1

`|x-2|=x-2`, for x=2+#. For all x > 2, the ratio is 1,

Explanation:

For `x=2-, |x-2|=-(x-2)`. So, for all x < 2, the ratio = `-1`.

The right and left limits, as `xto2` are `+-1`.

Overall, the graph of y = `|x-2|/(x-2)` is
`y = -1`, for x < 2 and y = 1, for x > 2. ,