How do you factor #2(3) + 2(5) + 2(6)#?

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Answer 1 · 2016-04-04T06:22:57

#2(3)+2(5)+2(6) = 2 xx 2 xx 7#

All of the terms are divisible by #2#, so you can separate that out first:

#2(3)+2(5)+2(6) = 2(3+5+6) = 2(14)#

Then factor #14# by noting that it is even (having an even last digit), so separate out another factor of #2# first:

#14 = 2 xx 7#

Then #7# is prime. It has no positive factors apart from #1# and #7#.

Putting it together we have:

#2(3)+2(5)+2(6) = 2(14) = 2 xx 2 xx 7#