What is the perimeter of a triangle with corners at #(3 ,6)#, #(2 ,3 )#, and #(4 ,9 )#?

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Answer 1 · 2016-04-04T11:57:06

Perimeter #P=sqrt10+sqrt10+2sqrt10=4sqrt10=12.6491#

Let #a# be the side from (3, 6) to (2, 3)
Let #b# be the side from (2, 3) to (4, 9)
Let #c# be the side from (3, 6) to (4, 9)

Use the distance formula

#d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

#a=sqrt((3-2)^2+(6-3)^2)=sqrt10#

#b=sqrt((2-4)^2+(3-9)^2)=sqrt(40)=2sqrt10#

#c=sqrt((3-4)^2+(6-9)^2)=sqrt(10)#

God bless....I hope the explanation is useful.