A cannon ball is launched (from the ground) at an angle of 35 degrees, and lands 2500 m from where it was launched. At what speed was the cannon ball launched?

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Answer 1 · 2016-04-05T15:13:41

#v_i=161,55 m/s#

#v_i:"initial velocity"#
#alpha:" angle"#
#g=9,81 m/s^2#
#x_m=2500 m#

#x_m=(v_i^2*sin2 alpha)/g#

#2500=(v_i^2*sin2*35)/(9,81)#

#v_i^2=(2500*9,81)/sin 70#

#v_i^2=24525/(0,9396926208#

#v_i^2=26098,96#

#v_i=161,55 m/s#