Question

How do you write the formula of vanadium (IV) carbonate?

Answer 1

Since it is specified as vanadium(IV), we know that we are using the `+4` cation, `\mathbf("V"^(4+))`, as the roman numerals correspond to the cationic charge.

Also, carbonate is the `\mathbf("CO"_3^(2-))` polyatomic ion.

Therefore, we are looking at `"V"^(4+)` and `"CO"_3^(2-)` in constructing this molecular formula, and we would get:

`color(blue)("V"("CO"_3)_2)`