Question

How do you differentiate `g(x) =e^(1-x)tanx` using the product rule?

Answer 1

`g'(x)=e^(1-x)sec^2x -e^(1-x)tanx`

Explanation:

let `f=e^(1-x)` and `g=tanx`

`f'=e^(1-x)*-1, g'=sec^2x`

`g'(x) = fg'+gf'`

`g'(x)=e^(1-x)sec^2x -e^(1-x)tanx`