How do you find the derivative of #y = arcsin(3x + 4)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Bdub Apr 8, 2016 #y'=3/sqrt(-9x^2-24x-15)# Explanation: #y'=1/sqrt(1-(3x+4)^2) *3#-> chain rule #y'=3/(sqrt(1-(9x^2+24x+16))#->FOIL #y'=3/sqrt(1-9x^2-24x-16)#->Distribute the negative 1 #y'=3/sqrt(-9x^2-24x-15)#->Combine like terms Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1832 views around the world You can reuse this answer Creative Commons License