A charge of #27 C# passes through a circuit every #3 s#. If the circuit can generate #72 W# of power, what is the circuit's resistance?

1 Answer
Apr 8, 2016

#R=8/9 Ohm#

Explanation:

#"given data:"#
#q=27C" charge"#
#Delta t=3 s" time interval"#
#P=72W" Power"#
#R=?" Resistance"#

#so" " P=I^2*R#

#"we must calculate the electric current I"#
#I=(Delta q)/(Delta t)#

#I=27/3=9A#

#cancel(72)=cancel(9)^2*R#

#8=9*R#

#R=8/9 Ohm#