How do you solve #54 + 3^3 - 13(8-6)^2#?

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Answer 1 · 2016-04-08T20:44:08

#29#

When solving an expression, you must use B.E.D.M.A.S., which stands for:

B rackets
E xponents
D ivision
M ultiplication
A ddition
S ubtraction

B.E.D.M.A.S. tells you the order in which operations should be done. Brackets is done first while subtraction is last.

#1#. To start, simplify the expression within the brackets.

#54+3^3-13color(red)((8-6))^2#

#=54+3^3-13color(red)((2))^2#

#2#. Simplify the terms with exponents.

#=54# #color(darkorange)(+3^3)-13color(darkorange)((2)^2)#

#=54# #color(darkorange)(+27)-13color(darkorange)((4))#

#3#. Since there is no division required, move on to multiplication.

#=54+27# #color(teal)(-13(4))#

#=54+27# #color(teal)(-52)#

#4#. Move on to addition.

#=color(purple)(54+27)-52#

#=color(purple)(81)-52#

#5#. Subtract the two numbers.

#=color(violet)(81-52)#

#=color(green)(|bar(ul(color(white)(a/a)29color(white)(a/a)|)))#