How many moles is 573.28 g of #AgCl#?

1 Answer
reudhreghs
Apr 9, 2016

#4.00molAgCl#

Explanation:

Find the relative mass of #AgCl# by adding together the relative atomic mass of each atom in the compound,

#107.868gmol^-1Ag + 35.45gmol^-1Cl = 143.318gmol^-1AgCl#

Divide the total mass of how much #AgCl# by the mass per mole to give you the number of moles,

#(573.28g)/(143.318gmol^-1)AgCl = 4.00molAgCl#

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