Question

How do you calculate `log_32 64`?

Answer 1

`6/5`

Explanation:

First you should see that
`64=2^6`
`32=2^5`

Then it's convenient to convert the `log_32` to `log_2` using this property
`log_a^b=log_c^b/log_c^a`

So
`log_32^64=log_2^64/(log_2^32) =log_2^(2^6)/(log_2^(2^5))=6/5`