Question #c66da

1 Answer
anor277
Apr 9, 2016

Approx. #3xx10^-3# #mol*L^-1#

Explanation:

#"Concentration, molarity"# #=# #"Moles of solute"/"Volume of solution"# #=# #(1.56*mol)/(500*L)# #=# #??# #mol*L^-1#.

By doing the calculation this way and including the units, I am introducing a reality check on my calculation. Do the resultant units make sense? Well, they are not #L*mol^-1# but #mol*L^-1#, as is required for a concentration.

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