How do you evaluate $cos (\frac{π}{4}) - (\frac{π}{4}) sin (\frac{π}{4})$ $Cos(pi/4) -(pi/4)sin(pi/4)$ ?

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How do you evaluate $cos (\frac{π}{4}) - (\frac{π}{4}) sin (\frac{π}{4})$ $Cos(pi/4) -(pi/4)sin(pi/4)$ ?

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Answer 1 · 2016-04-11T04:58:31

$r (π) = \frac{\sqrt{2}}{2} - \frac{π}{4} \frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{2} (1 - \frac{π}{4}) = \frac{\sqrt{2}}{2} \frac{(4 - π)}{4}$ $r(pi)=sqrt(2)/2-pi/4sqrt(2)/2=sqrt(2)/2(1- pi/4)=sqrt(2)/2((4- pi))/4$

Explanation:

Given : $r (\frac{π}{4}) = cos (\frac{π}{4}) - (\frac{π}{4}) sin (\frac{π}{4})$ $r(pi/4)=cos(pi/4) -(pi/4)sin(pi/4)$
Evaluate:
Solution :
$r (π) = \frac{\sqrt{2}}{2} - \frac{π}{4} \frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{2} (1 - \frac{π}{4}) = \frac{\sqrt{2}}{2} \frac{(4 - π)}{4}$ $r(pi)=sqrt(2)/2-pi/4sqrt(2)/2=sqrt(2)/2(1- pi/4)=sqrt(2)/2((4- pi))/4$

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How do you evaluate $cos (\frac{π}{4}) - (\frac{π}{4}) sin (\frac{π}{4})$ $Cos(pi/4) -(pi/4)sin(pi/4)$ ?

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Explanation:

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