Question

How do you solve `log_5 x=-3`?

Answer 1

`x=1/125=0.008`.

Explanation:

Inversely, `x=5^(-3)=1/5^3=1/125=0.008`.
Note that if `log_ax=b, x=a^b` and, inversely, if `x=a^b, log_a x=b`..