How do you simplify #4sqrt10 * 3 sqrt 6#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Sheffy Apr 13, 2016 #=24xxsqrt(15)# Explanation: #4sqrt10*3sqrt6# #= 4xx 3 xx sqrt(10xx6)# #=4 xx 3 sqrt (5 xx 2 xx 2 xx 3)# #=12 xx 2xxsqrt(5xx3)# #=24xxsqrt(5xx3)# #=24xxsqrt(15)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2191 views around the world You can reuse this answer Creative Commons License