Question

How do you determine if `2sin(x)cos(x)tan^2(x)` is an even or odd function?

Answer 1

Odd

Explanation:

Change x to `-x` in f(x).

If `f(-x)=-f(x)`, the function is odd.
If `f(-x)=f(x)`, the function is even.

`sin(-x)=-sin x, cos(-x)=cos x and tan(-x)=-tan x. Also, (-1)^2=1`

Here, `f(-x)=-f(x)`. So, the given function is odd. .