Consider the sequence -2, -4, -8, -16,... how do you find the 8th term of the sequence?
1 Answer
Apr 14, 2016
-256
Explanation:
This is a geometric sequence. The standard sequence being:
a , ar ,
#ar^2 , ar^3 , ............ , ar^(n-1)# where a represents the 1st term , r , the common ratio and
#ar^(n-1) , " the nth term "#
# ar^(n-1)" is used to find any term in the sequence " # In this question a = -2 , r
#=(-4)/(-2) =(-8)/(-4) = 2 " and n = 8 #
#rArr a_8 = -2xx(2)^7 = -2xx128 = - 256 #
