Question

An object with a mass of `4 kg` is hanging from a spring with a constant of `3 (kg)/s^2`. If the spring is stretched by `3 m`, what is the net force on the object?

Answer 1

`30.2N`

Explanation:

The net downward force on the object
= Downward Gravitational force on it - upward tension given by elongated spring
`=mg-kx=4kgxx9.8ms^-2-3(kg)/s^2xx3m=30.2N`