If a #2 kg# object is constantly accelerated from #0m/s# to #16 m/s# over # 8 s#, how much power musy be applied at #t=7#?

Question

1296 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-16T21:09:57

#P=2*2*14=56 W#

#m=2kg" mass of object"#
#v_i=0 m/s" initial velocity of object"#
#v_f=16 m/s" last velocity of object"#
#Delta t=8 s#

#a=(v_l-v_i)/(Delta t)" acceleration of object"#

#a=(16-0)/8#

#a=16/8=2 m/s^2#

#v=a*t#
#v=2*7=14 m/s" velocity of object at t=7"#

#P=m*a *v#

#P=2*2*14=56 W#