What is the general method for integrating by parts?

1 Answer
Apr 18, 2016

#intu# #dv=uv-int# #v# #du#

Explanation:

The trick with doing integration by parts comes in choosing your #u# and #dv# accordingly. If you choose poorly, the problem will usually become harder.

For example, consider #intxsinx# #dx#.

If you let #u=sinx# and #dv=x# #dx# (and accordingly #du=cosx# #dx# and #v=1/2x^2#) you will end up with

#intxsinx# #dx=1/2x^2sinx-1/2intx^2cosx# #dx#.

You can try to evaluate the integral #intx^2cosx# #dx# but if you make similar #u# and #dv# choices this problem will continue to get more complicated.

Instead, for #intxsinx# #dx#, let #u=x# and #dv=sinx# #dx# (and accordingly #du=1# #dx# and #v=-cosx#). Then you get

#intxsinx# #dx=-xcosx-int-cosx*(1)# #dx#

#=-xcosx+intcosx# #dx=-xcosx+sinx+C#.

This way, you can actually do the problem.

Now you are probably thinking "Is there a way to know to to make #u# and #dv# so I don't have to go through this process of trial and error?"

The answer is yes. Use the acronym LIPET to remember the order of choosing #u#, in order of best to choose to worst to choose.

BEST
L: logarithmic stuff
I: inverse trig stuff
P: polynomialish stuff
E: exponential stuff
T: trig stuff
WORST

Trial and error should help explain why this order is helpful.