Question

How do you simplify `5 ln (1/e^2)`?

Answer 1

`5ln(1/(e^2))=color(green)(-10)`

Explanation:

Remember: `ln a = k` is equivalent to `e^k=a`

Considering `ln(1/(e^2))=k`
`color(white)("XXX")a=1/(e^2)=e^(-2)`
so
`color(white)("XXX")k=-2`

If `ln (1/(e^2))=-2`
then
`color(white)("XXX")5ln(1/(e^2))=5xx(-2)=-10`