Question

How do you determine the limit of `(x^2 - 2x - 8)/(x^2 - 5x + 6)` as x approaches `2^+`?

Answer 1

`=oo`

Explanation:

`lim_(x->2^+) ((x-4)(x+2))/((x-2)(x-3)`

`= ((-2)(4))/(0*-1)`

`=8/0`

`=oo`