How do you evaluate #(e^(4x) -1 -4x) / (x^2)# as x approaches infinity?
1 Answer
Apr 23, 2016
The answer is infinity.
Explanation:
It takes some logic to solve this one. Plug in infinity into the equation...you'll get:
Infinity squared? That's a huge number. But something to the power of infinity? That's even bigger.
Remember, infinity is simply a place holder for a large number...I perceive the above equation as such...
Super mega large number / large number =
The answer comes out as
