What is the standard form of #y= (x+7)(x-8)^2 #?

1 Answer
Edmund Liew
Apr 25, 2016

#y = (x+7)(x-8)(x-8)#
See below..

Explanation:

#(x-8)^2# means #(x-8)(x-8)#

#y = (x+7)(x-8)(x-8)#
#y = (x+7)(x^2-8x-8x+64)#
#y =(x+7)(x^2-16x+64) #

then break the (x+7) up,
#x(x^2-16x+64)+7(x^2-16x+64)#

#=x^3-16x^2+64x+7x^2-112x+448#

#=x^3-9x^2-48x+512# is your final answer

Note: PLEASE PLEASE PLEASE! Be very careful with positives and negatives!!

Related questions
See all questions in Polynomials in Standard Form
Impact of this question
1809 views around the world
You can reuse this answer
Creative Commons License