Question

516 mL of a 3.82 M sodium sulfate (`Na_2SO_4`) solution is diluted with 0.875 L of water. What is the new concentration in molarity?

Answer 1

Approx. `1.4*mol*L^-1`

Explanation:

`"Molarity "= " Moles of solute"/"Volume of solution (L)"`

`=` `(516xx10^-3*cancelLxx3.82*mol*cancel(L^-1))/(0.516*L+0.875*L)`

`=` `(1.97*mol)/(1.391*L)`

`~=` `1.4*mol*L^-1`