How do you solve #1/2(c+6)=7#?

1 Answer
Apr 27, 2016

#c=8#

Explanation:

First of all, we must know that if you apply the same operation to both sides of the equality, the final result does not change. The aim is always to isolate the variable. Since the left side is being divided by 2, we will start by multiplying both sides by 2, therefore eliminating the division:

#cancel(2*(1/2))*(c+6)=7*2#
#c+6=14#

Then subtract 6 to both sides:

#c+cancel(6-6)=14-6#
#c=8#

This method also works if you think about sending a number to the other side of the equality in the inverse operation. First, you sent #/2# as #times2#, then #+6# as #-6# to the other side .