What is the molality of acetone in a solution composed of 255 g of acetone, #(CH_3)_2CO#, dissolved in 200 g of water?

1 Answer
anor277
Apr 28, 2016

#"Molality"# #=# #"Moles of solute"/"Kilograms of solvent"#. Here we consider acetone to be the #"solute"#.

Explanation:

Given that definition, and also that the molar mass of acetone is #58.08*g*mol^-1#, we can calculate the molality of the solution.

#"Molality"# #=# #(255*cancelg)/(58.08*cancelg*mol^-1)# #xx# #1/(200*cancelgxx10^-3*kg*cancel(g^-1)#

#=# #??*mol*kg^-1#.

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