Question

How do you calculate `log_6 (2)`?

Answer 1

log 2/log 6 = 0.386853, nearly

Explanation:

Use `log_b a = log_c a/log_c b`, where c is at your choice.

Let us choose c as either 10 or e. Then

`log_6 2=log_10 2/log_10 6=ln 2/ln 6=0.386853`, nearly.

I am sure that this comparison, using different bases, would reinforce the formula used, in the long term memory.