Question #ec7e1
1 Answer
Here's how you can do that.
Explanation:
All you have to do here is use the given weight by volume percent concentration,
A solution's weight by volume percent concentration tells you how many grams of solute you get for every
In your case, the solution is said to be
Now, the problem tells you that you have a mass of solute of
#color(purple)(|bar(ul(color(white)(a/a)color(black)("1 g" = 10^3"mg")color(white)(a/a)|)))#
You will have
#2.5 color(red)(cancel(color(black)("mg"))) * "1 g"/(10^3color(red)(cancel(color(black)("mg")))) = "0.0025 g"#
So, you know that the solution contains
#0.0025 color(red)(cancel(color(black)("g solute"))) * overbrace("100 mL solution"/(0.80color(red)(cancel(color(black)("g solute")))))^(color(blue)("= 0.80% w/v")) = "0.3125 mL solution"#
Rounded to two sig figs, the answer will be
#"volume of solution" = color(green)(|bar(ul(color(white)(a/a)"0.31 mL"color(white)(a/a)|)))#