Question

A charge of `36 C` passes through a circuit every `6 s`. If the circuit can generate `36 W` of power, what is the circuit's resistance?

Answer 1

`=1Omega`

Explanation:

We know Power ,`P = I^2xxR`,where I = current and R = resistance
Again `I =q/t=36/6A`,where q = chatge and t = time of passing q charge through the conductor

So `R =P/I^2=36/6^2=1Omega`