Question

How do you find `abs( -2+i )`?

Answer 1

`|-2+i| = sqrt(5)`

Explanation:

Given a complex number `a+bi`, that number's modulus, denoted `|a+bi|`, is given by

`|a+bi| = sqrt(a^2+b^2)`

In this case, that gives us

`|-2+i| = sqrt((-2)^2+1^2) = sqrt(4+1) = sqrt(5)`