What is the solution set for #(5x)/11 < 2#?

1 Answer
May 4, 2016

#x in [-oo,22/5[color(white)(22/5)#

Explanation:

Manipulate as you would normally do for an equation so that you have #x# on one side and everything else on the other giving:

#x<22/5#

So the solution set is from and including negative infinity up to but not including #22/5#

I believe the notation is:#" "[-oo,22/5[color(white)(22/5)#